REMEMBER: The number of different arrangements of $$ n $$ objects taken all at a time is given by: $$ n P_{n}=n $$ ! when; 1. The $$ n $$ objects are distinct 2. Once an object is used it cannot be repeated, and 3. Order is important

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Parry Matthews · Accepted Answer

The number of different arrangements of $$ n $$ distinct objects taken all at a time is $$ n! $$, which means $$ n 	imes (n-1) 	imes (n-2) 	imes \ldots 	imes 3 	imes 2 	imes 1 $$. Order matters, and no object is repeated in an arrangement.

REMEMBER: The number of different arrangements of \( n \) objects taken all at a time is given by: \( n P_{n}=n \) ! when; 1. The \( n \) objects are distinct 2. Once an object is used it cannot be repeated, and 3. Order is important

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REMEMBER: The number of different arrangements of \( n \) objects taken all at a time is given by: \( n P_{n}=n \) ! when; 1. The \( n \) objects are distinct 2. Once an object is used it cannot be repeated, and 3. Order is important

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