Solve. Hint: Let \( \mathrm{u}=\mathrm{x}^{\frac{1}{3}} \). \( \mathrm{x}^{\frac{2}{3}}-\mathrm{x}^{\frac{1}{3}}-20=0 \) \( \mathrm{x}=\square \) (Simplify your answer. Type an exact answer, using radicals and \( i \) as needed. Use a comma to separate answers as needed.)

\( x y+8=24 \quad \) where \( y=2 \)

\[ y=-3 x^{2}+12 x-15 \] Write your answer as an inequality using \( x \) or \( y \) as appropriate. Or, you may instead click on "Empty set" or "All reals" as the answer.

\[ y=x^{2}+8 x+18 \] Write your answer as an inequality using \( x \) or \( y \) as appropriate. Or, you may instead click on "Empty set" or "All reals" as the answer

If \( (2 a-5)(3 a-2)=6 a^{2}+k a+10 \), then \( k= \) \( \begin{array}{llll}\text { (a) } 15 & \text { (b) } 19 & \text { (c) }-19 & \text { (d) } 6\end{array} \)

1) \( (3 x)\left(2 x^{2}\right) \) 4) \( \left(x^{3}\right)\left(x^{2}+x\right)\left(3 x^{3}\right) \) 7) \( \left(x^{4}+3 x^{3}+2 x^{2}+11 x\right)\left(x^{3}\right) \)