\( \rightarrow 6 x ^ { 2 } + 2 x - 4 = 0 \)

Jika \( \left(\begin{array}{cc}-2 & 2 \\ 5 & y\end{array}\right)\left(\begin{array}{ll}5 & 3 \\ x & 4\end{array}\right)=\left(\begin{array}{cc}-6 & 2 \\ 27 & 19\end{array}\right) \), cari nilai \( x \) dan \( y \). If \( \left(\begin{array}{cc}-2 & 2 \\ 5 & y\end{array}\right)\left(\begin{array}{ll}5 & 3 \\ x & 4\end{array}\right)=\left(\begin{array}{cc}-6 & 2 \\ 27 & 19\end{array}\right) \), find the value of \( x \) and \( y \).

Given that \( g(x)=\sqrt{\frac{2 x+3}{5 x+6}} \), find \( g^{-1}(x) \) \( g^{-1}(x)=x^{2}-3 x \)

ivaret som et produkt av to pot \[ \text { b } \frac{3^{12} \cdot 12^{2}}{6^{3}} \]

5. Solve \( x^{2}+4 x+3>0 \)

1.Решить уравнение: \( \begin{array}{lll}\text { a) } \sqrt{x+3}=\sqrt{5-x} & \text { б) } \quad \sqrt{12+3 x}=2 & \text { в) } \quad x=1+\sqrt{x+11}\end{array} \)