Example 5. For the differential equation \( y^{2}+x^{2} \frac{d y}{d x}=0 \), we found that the solution \( y(x) \equiv 0 \) was a singular point and this solution can not be obtain from the general solution \( y(x)=\frac{x}{(x-1)} \) by any choice of the constant \( c \).

\( 16 d ^ { 4 } y / d x ^ { 4 } + 24 d ^ { 2 } y / d x ^ { 2 } + 9 y = 0 \)

\( \int _ { 0 } ^ { 45 } \sec ^ { 4 } x d x \)

\( \begin{aligned} \text { 40. } y=\frac{b}{a} \sqrt{a^{2}-x^{2}} & \frac{d y}{d x} & =-\frac{b^{2} x}{d^{2} y} \\ \text { H. } y=\left(a^{2 / 3}-x^{2 / 3}\right)^{3 / 3} & \frac{d y}{d x} & =-\sqrt[3]{\frac{y}{x}}\end{aligned} \)

Un agricultor necesita calcular el área bajo la curva de una función que representa tasa de crecimiento de sus cultivos, \( g(t)=t 3-t \), en el intervalo d tiempo \( [0,2] \). El área bajo la curva de la función \( g(t) \) en ese intervalo es a. 10 b. 8 c. 4 d. 6

Sociologists have found that crime rates are influenced by temperature. In a town of 100,000 people, the crime rate has been approximated as \( \mathrm{C}=\frac{1}{10}(\mathrm{~T}-60)^{2}+100 \), where C is the humber of crimes per month and \( T \) is the average monthly temperature in degrees Fahrenheit. The average temperature for May was \( 72^{\circ} \) and by the end of May the temperature was rising at the rate of \( 7^{\circ} \) per month. How fast is the crime rate rising at the end of May? At the end of May, the crime rate is rising by (Simplify your answer.)