268. Решите уравнение: \( \begin{array}{l}\text { a) }(y+2)\left(y^{2}-2 y+4\right)-y(y-3)(y+3)=44 \text {; } \\ \text { б) }(m-3)\left(m^{2}+3 m+9\right)-m(m+2)(m-2)=13 \\ \text { (B) }(3 a+1)\left(9 a^{2}-3 a+1\right)-3 a\left(9 a^{2}+4\right)=25 \text {; } \\ \text { (A) }(2 n-1)\left(4 n^{2}+2 n+1\right)-4 n\left(2 n^{2}-5\right)=21 \text {. }\end{array} \)

\( x^{3}-7 x+10 \) при \( x=-2 \)

A. Let \( p(x)=2 x^{2}+5 x-3, m(x)=2 x-1 \), and \( h(x)=\frac{x+1}{x-2} \) Find: 1. \( (m-p)(x) \) 2. \( p(5)+m(3)-h(1) \) 3. \( \frac{m(x)}{p(x)} \) 4. \( p(x+1) \) 5. \( p(3)-3(m(2) \) B. Given the following: - \( m(x)=5 x-3 \) - \( n(x)=x+4 \) - \( c(x)=5 x^{2}+17 x-12 \)

\( \sqrt{3}(x-y-2)+2 x-y=7 \) tenglamani butun sonlarda yeching. \( \begin{array}{ll}\text { A) }(2 ; 1) & \text { B) }(5 ; 3) \\ \text { C) }(3 ; 4) & \text { D) }(6 ; 4)\end{array} \)

В \( 6 x^{5}-5 \quad \) Г \( 2 x^{3}-15 x^{2} \) многочлена на многочлен: \( (x-1) \) (

Stessa base Đesercizio guidal Esegui, usando le proprietà. a. \( 5^{9} \cdot 5=5 \) b. \( 12 \cdot 12^{3}= \) c. \( 3,2^{6} \cdot 3,2^{5}= \) d. \( 41^{0} \cdot 41= \) e. \( 8^{2} \cdot 8^{3} \cdot 8^{4}= \) f. \( 0,15^{6} \cdot 0,15 \cdot 0,15^{0}= \)