\( \left. \begin{array} { | l | } \hline \text { Solve each proportion. } \\ \hline \frac { 2 } { 3 } = \frac { x } { 24 } \\ \hline 6 . \quad \frac { x } { 5 } = \frac { 28 } { 100 } \\ \hline 8 . \quad \frac { x - 3 } { 3 } = \frac { 5 } { 8 } \\ \hline \end{array} \right. \)

\( 14 d + 12 a + 5 \)

(a4) The solution set of the equation : \( \sqrt[3]{x^{2}}-3 \sqrt[3]{x}+2=0 \) is \( \{1,8\} \) \( \begin{array}{llll}\text { (a) }\{1, & \text { (b) }\{9,3\} & \text { (c) }\{8\} & \text { (d) }\{1\}\end{array} \)

Add. \[ \frac{-5}{8 w^{2} y}+\frac{3}{4 w y^{2}} \] Simplify your answer as much as possible.

4. Diketahui \( f(x)=a \), maka \( f(2)=\ldots \) A. \( 2 f(x) \) B. \( 2 a \) C. 2 D. \( f(x) \) E. \( a \)

The height \( h \), in feet, of a projectile can be modeled by the equation \( h(t)=-16 t^{2}+v_{0} t+h_{0} \) where \( t \) is the time in seconds, \( h_{0} \) is the projectile's initial height in feet, and \( v_{0} \) is the projectile's initial vertical velocity in feet per second. Solve the projectile motion problem by completing the square. A soccer player kicks a soceer ball from the ground with an initial vertical velocity of var : \( v 0 \) feet per secoad. When will the ball land back on the ground? Round to the nearest tenth of a second. Enter the correct value in the box. Show Hints The ball will land on the ground again in \( \square \) second(s).