If \( x-6=0 \) is one of the solutions df the equation \( x+\frac{40}{x}=16 \), determine ONE value of \( y \) for which \( 2 y+3+\frac{40}{2 y+3}=16 \)

Rewrite the following as a single logarithmic expression: \( 3 \log _{b} m-2 \log _{b} n \) (1 point) \( \log _{b}\left(\frac{3 m}{2 n}\right) \) \( \log _{b}\left(m^{3} n^{2}\right) \) \( \log _{b}\left(\frac{m^{3}}{n^{2}}\right) \) \( \log _{b}\left(m^{3}-m^{2}\right) \)

Solve \( \log _{2}\left(\log _{4} x\right)=3 \) (1 point) \[ \begin{array}{l}x=262,144 \\ x=4,096 \\ x=65,536 \\ x=6,561\end{array} \]

\( \frac{3x-4}{6}=^{\frac{7}{}}8 \)

Select the equation that can be used to solve \( \log _{4}(x+4)+\log _{4}(x-2)=2 \). (1 point) \( x^{2}+2 x-8=0 \) \( x^{2}+2 x-24=0 \) \( x^{2}-2 x-24=0 \) \( x^{2}-2 x-10=0 \)

Задание 2. Решить неравенства а) \( |3 x-3|>1 \) б) \( |x+3|<x-2 \) в) \( |3 x+2| \leq|5 x-4| \)