Set up the definite integral required to find the area of the region between the graph of $$ y=13-x^{2} $$ and $$ y=24 x+148 $$ over the interval $$ -5 \leq x \leq 3 $$.

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Young Flynn · Accepted Answer

The definite integral to find the area between the curves $$ y = 13 - x^2 $$ and $$ y = 24x + 148 $$ over the interval $$ -5 \leq x \leq 3 $$ is: $$ A = \int_{-5}^{3} (x^2 + 24x + 135) \, dx $$

Set up the definite integral required to find the area of the region between the graph of \( y=13-x^{2} \) and \( y=24 x+148 \) over the interval \( -5 \leq x \leq 3 \).

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Set up the definite integral required to find the area of the region between the graph of \( y=13-x^{2} \) and \( y=24 x+148 \) over the interval \( -5 \leq x \leq 3 \).

Solución ThothAI de Upstudy

Respuesta rápida

Solución paso a paso

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