ctividad evaluativa: 1) Hallar la ecuación de una función lineal que pase por el punto (1;3) y tenga pendiente 4 . 2) Hallar la ecuación de la recta que sea paralela a \( Y=\frac{5}{3} X+4 \), y que pasa por el punto \( \left(-1 ;-\frac{2}{3}\right) \). Graflcar ambas rectas. 3) Hallar la ecuación de la recta que pase por los puntos \( (2 ; 6) \) y \( (-3 ; 1) \), luego determinar una recta perpendicular a la anterior que pase por el origen de coordenadas, Graficar ambas rectas. 4) Hallar la ecuación de la recta que sea perpendicular a \( \frac{1}{5} X-1+Y=0 \), y que pase por el punto ( \( \left.1 ;-1\right) \).

Rewrité the equation in \( A x+B y=C \) form. Use integers for \( A, B \), and \( C \). \[ y-3=6(x-4) \]

Simplify the expression. \[ x^{-\frac{1}{4}} \] \( x^{\frac{1}{2}} x^{\frac{1}{3}} \) Write your answer using only positive exponents. Assume that all variables are positive real numbers.

11) Sarah is planning a birthday party for her friends and family and wants to make sure that the number of total guests is neither too few nor too many. She has space to comfortably host between 15 and 30 total guests. Sarah has 4 family members that are already planning on coming and is trying to decide how many friends she can invite. If \( x \) represents the number of friends she can invite, write a compound inequality that describes the possible number of guests she can invite.

he holes of the graph of a rational function are determined by finding values of \( x \) such that \( (x-a) \) is a common factor of the numerator and the \[ g(x)=\frac{(x-7)(x+5)}{(x-6)(x+6)} \] The factored rational function -Select-v have any common factors with values that make the denominator zero. Find any holes of the graph. (If an answer does not exist, enter DNE.) \( (x, y)=( \)

\( \begin{array}{r}-2 x-3 y=8 \\ 5 x+y=6\end{array} \) 4) What is the solution to this system of equations? \( (\square, \square \)