— $$ \begin{array}{llll} ext { 9. } \sqrt{2 x+22}-7=x & ext { b. } 9 ext { and }-3 & ext { c. }-3 & ext { d. }-9 ext { and }-3\end{array} $$

Question

— $$ \begin{array}{llll}	ext { 9. } \sqrt{2 x+22}-7=x & 	ext { b. } 9 	ext { and }-3 & 	ext { c. }-3 & 	ext { d. }-9 	ext { and }-3\end{array} $$

Perkins Bush · Accepted Answer

方程的解为 $$ x = -3 $$ 和 $$ x = -9 $$。正确答案是 d. -9 和 -3。

— \( \begin{array}{llll}\text { 9. } \sqrt{2 x+22}-7=x & \text { b. } 9 \text { and }-3 & \text { c. }-3 & \text { d. }-9 \text { and }-3\end{array} \)