Using the Law of Sines to solve the triangle if \( \angle A=111^{\circ}, a=34, b=14 \). If no answer exists, enter DNE for all answers. \( \angle B \) is 22.6 \( \angle C \) is 46.4 \( c= \) Assume \( \angle A \) is opposite side \( a, \angle B \) is opposite side \( b \), and \( \angle C \) is opposite side \( c \).

Without using a calculator, compute the sine and cosine of \( 120^{\circ} \) by using the reference angle. What is the reference angle? \( \square \) degrees. In what quadrant is this angle? \( \square \) (answer \( 1,2,3 \), or 4 )

Without using a calculator, compute the sine and cosine of \( \frac{3 \pi}{4} \) by using the refer What is the reference angle? \( \square \) radians. In what quadrant is this angle? \( \sin \left(\frac{3 \pi}{4}\right)=\square \) \( \cos \left(\frac{3 \pi}{4}\right)=\square \)

\begin{tabular}{l} Resoluer el siguiente triangub. \\ \hline \( 5^{\circ} \) \\ \( \sin \alpha \)\end{tabular}\( \frac{B}{\operatorname{sen} \beta} \)

\( \frac { \sin A } { 1 + \cos A } + \frac { 1 - \operatorname { cosec } A } { \sin A } = 2 \operatorname { cosec } A \)

\begin{tabular}{l} (b) Using the formula \( \operatorname{Sin} 2 A=2 \operatorname{Sin} A \operatorname{Cos} A \) \\ solve the equation \( \sin 2 x-\cos x=0 \) \\ in the interval \( 0^{\circ} \leq x \leq 360^{\circ} \) \\ \hline\end{tabular}