Suppose that the functions \( g \) and \( h \) are defined as follows. \[ \begin{aligned} g(x)=5-3 x^{2} \\ h(x)=9-2 x\end{aligned} \] (a) Find \( \left(\frac{g}{h}\right) \) (2). (b) Find all values that are NOT in the domain of \( \frac{g}{h} \). If there is more than one value, separate them with commas. (a) \( \left(\frac{g}{h}\right) \) (2) = (b) Value(s) that are NOT in the domain of \( \frac{g}{h}: \square \)

b) \( 5^{0}+\frac{1}{3} \cdot\left[\left(3-\frac{1}{5}\right) \cdot 5^{-2}+2 \cdot\left(1-\frac{2}{5}\right)^{3}\right]: \frac{4}{3} \)

1. \( \frac{4 x+5}{13}=\frac{8}{9} \)

\begin{tabular}{l} B) DIRECTIONS: Solve each equation using the QUADRATIC FORMULA: \( x= \) \\ \( \qquad \)\begin{tabular}{|l|l|l}\hline 5\( ] c^{2}-5 c+4=0 \) & \( 6] b^{2}-b-12=0 \) & \( 73 a^{2}-4 a-12=0 \) \\ \hline\end{tabular} \\ \hline\end{tabular}

Simplificar y obtener la minima expresión: \( \frac{\frac{b}{a}+\frac{a-2 b}{b}}{\left(\frac{a^{2}+3 a b+3 b^{2}}{b}+\frac{b^{2}}{a}\right) \cdot(a-b)^{2}} \)

For the following system to be consistent, \( \left\{\begin{array}{l}6 x_{1}-3 x_{2}-2 x_{3}=-6 \\ 5 x_{1}-8 x_{2}+k x_{3}=-4 \\ -7 x_{1}+4 x_{2}+7 x_{3}=8\end{array}\right. \) we must have \( k \neq \square \) You may enter your answer as a fraction.