What is the solution to the equation? \( \begin{array}{l}\frac{1}{2} \ln (x+17)=\ln \left(x^{2}-9\right)-\ln (x+3) \\ x=-8 \text { and } x=1 \\ x=8 \text { only } \\ x=1 \text { only } \\ 0 x=-1 \text { and } x=8\end{array} \)

Simplify the expression: \( 3 z-6+7-3 z+9 \)

\( \left. \begin{array} { r l r l } { 5 x + 3 x + 2 x } & { = } & { 7 y + 5 y - 9 y } & { = } \\ { 2 a + 4 a + 6 a } & { = } & { 2 a + 3 a - 5 a } & { = } \\ { 3 x + 5 x - 6 x } & { = } & { 10 x - 5 x + 12 x } & { = } \\ { - 5 y - 8 y } & { = } & { - 11 b - 7 b } & { = } \end{array} \right. \)

Simplify. \[ \frac{x^{2} y^{6}}{x^{3} y^{6}} \]

Graph the solution set of the following system of inequalities. \[ \begin{array}{l}x+y \leq 4 \\ y \geq x^{2}-3\end{array} \]

Which of the following equations represents a line that passes through the points \( (-4,11) \) and \( (6,-9) \) ? \[ \begin{array}{l}\text { I. } y=-2 x+3 \\ \text { II. } y+9=-2(x-9) \\ \text { Answer } \\ \text { Neither } \\ \text { II only }\end{array} \] I only I II