Which quadratic function has an axis of symmetry of $$ x=2 $$ and a minimum value of -4 ? $$ \begin{array}{ll} ext { (A) } y=3(x+2)^{2}-4 & (B) y=-3(x+2)^{2}+4 \ ext { (C) } y=3(x-2)^{2}-4 & ext { (D) } y=-3(x-2)^{2}+4\end{array} $$ $$ \begin{array}{ll} ext { (A) } y=\end{array} $$

Question

Which quadratic function has an axis of symmetry of $$ x=2 $$ and a minimum value of -4 ? $$ \begin{array}{ll}	ext { (A) } y=3(x+2)^{2}-4 & (B) y=-3(x+2)^{2}+4 \ 	ext { (C) } y=3(x-2)^{2}-4 & 	ext { (D) } y=-3(x-2)^{2}+4\end{array} $$ $$ \begin{array}{ll}	ext { (A) } y=\end{array} $$

Marsh Li · Accepted Answer

The correct answer is C. $$ y = 3(x - 2)^2 - 4 $$

Which quadratic function has an axis of symmetry of \( x=2 \) and a minimum value of -4 ? \( \begin{array}{ll}\text { (A) } y=3(x+2)^{2}-4 & (B) y=-3(x+2)^{2}+4 \\ \text { (C) } y=3(x-2)^{2}-4 & \text { (D) } y=-3(x-2)^{2}+4\end{array} \) \( \begin{array}{ll}\text { (A) } y=\end{array} \)

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Which quadratic function has an axis of symmetry of \( x=2 \) and a minimum value of -4 ? \( \begin{array}{ll}\text { (A) } y=3(x+2)^{2}-4 & (B) y=-3(x+2)^{2}+4 \\ \text { (C) } y=3(x-2)^{2}-4 & \text { (D) } y=-3(x-2)^{2}+4\end{array} \) \( \begin{array}{ll}\text { (A) } y=\end{array} \)

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