$$ \left(\frac{625}{16}\right)^{x+1}=\left(\frac{2}{5}\right)^{x-1} $$ A. $$ \left\{-\frac{3}{10}\right\} $$ B. $$ \left\{-\frac{6}{5}\right\} $$ c. $$ \left\{\frac{3}{5}\right\} $$ D. $$ \left\{-\frac{3}{5}\right\} $$

Question

Vaughn Warner · Accepted Answer

The correct answer is D. $$ \left\{-\frac{3}{5}\right\} $$.

\( \left(\frac{625}{16}\right)^{x+1}=\left(\frac{2}{5}\right)^{x-1} \) A. \( \left\{-\frac{3}{10}\right\} \) B. \( \left\{-\frac{6}{5}\right\} \) c. \( \left\{\frac{3}{5}\right\} \) D. \( \left\{-\frac{3}{5}\right\} \)

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Solución paso a paso

\( \left(\frac{625}{16}\right)^{x+1}=\left(\frac{2}{5}\right)^{x-1} \) A. \( \left\{-\frac{3}{10}\right\} \) B. \( \left\{-\frac{6}{5}\right\} \) c. \( \left\{\frac{3}{5}\right\} \) D. \( \left\{-\frac{3}{5}\right\} \)

Solución ThothAI de Upstudy

Respuesta rápida

Solución paso a paso

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