5. Fourth term of arith sequence is 11 , and the \( 6^{2} \) term is 17 . Find the second term. \( a_{4}=11 \quad a_{6}=17 \quad a_{1}+(n-1) \)

Find the range of the quadratic function, \[ y=-3 x^{2}-12 x-15 \] Write your answer as an inequality using \( x \) or \( y \) as appropriate, Or, you may instead click on "Empty set" or "All reals" as the answer, प<ロ \( \square>\square \)

\( x-4+2 x=8 \) whats \( x+3 \)

Simplify. \[ \frac{3 x^{2}-6 x}{4 x^{2}-8 x} \]

Solve the equation. If necessary, round to the nearest thousandth. \( 7^{x+3}=6^{x} \) A. \( \{37.87\} \) B. \( \{-39.33\} \) C. \( \{-37.87\} \) D. \( \{-36.41\} \)

\( | \frac { 2 x - 1 } { x + 1 } - 2 | < \varepsilon \)