A manufacturer produces 1200 computers each week. After week 1 he increases production by: Scheme I: 80 computers each week. Scheme II: \( 5 \% \) each week. \( \begin{array}{ll}\text { (i) Find the output in week } 20 \text { under each scheme. } \\ \text { (ii) Find the total output over the first } 20 \text { weeks under each scheme. } \\ 5.17 .2 & \begin{array}{l}\text { Calculate for schemel-I and II, the week in which production exceeds } \\ \text { 8000. }\end{array}\end{array} \)

Consider the line \( y=\frac{5}{2} x-3 \). Find the equation of the line that is perpendicular to this line and passes through the point \( (2,-5) \). Find the equation of the line that is parallel to this line and passes through the point (2, -5). Note that the ALEKS graphing calculator may be helpful in checking your answer. Equation of perpendicular line:

Your answer Is Incorrect. \( 9 \times(3+4)=(\square \times 3)+(\square \times 4) \) Use the distributive property to fill in the blanks below.

Solve the equation. \( \ln (8 \mathrm{x}+15)-\ln \mathrm{x}=\ln 9 \) Select the correct choice below and, if necessary, fill in th A. The solution set is \( \{ \) B. The solution is the empty set. (Simplify your answer. Use a comma to separate a

Solve the equation by factoring. Select the correct solution. \( 6 x^{2}-5 x-4=0 \) \( \begin{array}{ll}\text { O } & \text { A) } x=-\frac{4}{3},-\frac{1}{2} \\ \text { O } & \text { B) } x=-\frac{1}{2}, \frac{4}{3} \\ \text { O } & \text { C) } x=-\frac{4}{3}, \frac{1}{2} \\ \text { - } & \text { D) } x=\frac{1}{2}, \frac{4}{3}\end{array} \)

b. \( -0.5 p+\frac{1}{2} p-2.75+\frac{2}{3} \)