Change the exponential statement to an equivalent statement involving a logarithm. \( 6561=9^{4} \) The equivalent logarithmic statement is \( \square \). (Type an equation.)

2. The value of \( \frac{(0.1)^{2}-(0.01)^{2}}{0.0001}+1 \) is

Evaluate using your calculator and round to 4 decimal places. \( \log _{8} 10=\square \)

Indicate between which two integers the following root lies \( ?<\sqrt{13}< \) ?

Hisoblang: \( \sqrt{66^{2}-44^{2}-22^{2}} \) \( \begin{array}{llll}\text { A) } 22 & \text { B) } 44 & \text { C) } 0 & \text { D) } 33\end{array} \)

e) \( \sqrt[2]{\left(\frac{49}{9}\right)^{11} \cdot\left(\frac{49}{9}\right)^{-4}:\left(\frac{98}{18}\right)^{6}: \frac{196}{36}+[3-(0, \hat{6}-1)]^{2}}= \)