Je détermine l'image d'un nombre par une fonction On considère la fonction \( f \) telle que \( f(x)=\frac{1}{x}+x \). Calculer: \( \begin{array}{lll}\text { a. } f(1) & \text { b. } f(-1) & \text { c. } f(2) \\ \text { d. } f(4) & \text { e. } f(-10) & \text { f. } f(3)\end{array} \)

Use the distributive property to fill in the blanks below. \( 6 \times(9-4)=(\llbracket \times 9)-(\square \times 4) \) Introduction to the distributive property

Solve the equation by factoring. Select the correct solution. \( 6 x^{2}-5 x-4=0 \) \( \begin{array}{ll}\text { O } & \text { A) } x=-\frac{4}{3},-\frac{1}{2} \\ \text { O } & \text { B) } x=-\frac{1}{2}, \frac{4}{3} \\ \text { O } & \text { C) } x=-\frac{4}{3}, \frac{1}{2} \\ \text { - } & \text { D) } x=\frac{1}{2}, \frac{4}{3}\end{array} \)

b. \( -0.5 p+\frac{1}{2} p-2.75+\frac{2}{3} \)

1 Graph \( y-2=\frac{2}{3}(x-3) \)

Consider the line \( y=\frac{5}{2} x-3 \). Find the equation of the line that is perpendicular to this line and passes through the point \( (2,-5) \). Find the equation of the line that is parallel to this line and passes through the point (2, -5). Note that the ALEKS graphing calculator may be helpful in checking your answer. Equation of perpendicular line: