\( \begin{array}{ll}\text { 1.1.1 } & x=\frac{4}{x}+3 \\ \text { 1.1.2 } & 2 x^{2}=-x+5(\text { Are the roots real or Unreal) }\end{array} \)

Solve the absolute value inequality. \( |x-6| \geq 1 \) A. The solution set in interval notation is (Simplify your answer.) B. The solution set is \( \varnothing \).

Determine whether the following equation defines \( y \) as a function of \( x \). \[ x^{2}+y=49 \] Does the equation \( x^{2}+y=49 \) define \( y \) as a function of \( x \) ? Yes No

7. \( \begin{aligned} y & =2 x+8 \\ y & =-2 x\end{aligned} \)

\[ \begin{array}{l}|x+6| \leq 7\end{array} \] Solve the absolute value inequality. A. The solution set in interval notation is (Simplify your answer.) The solution set is \( \varnothing \).

lify \( \left(\frac{x^{-2} y^{-1 / 3}}{x^{-5 / 3} y^{-2 / 3}}\right)^{3} \) so there