Consider this product. $$ \frac{x^{2}-3 x-10}{x^{2}-6 x+5} \cdot \frac{x-2}{x-5} $$ The simplest form of this product has a numerator of $$ x+2 $$ The expression has an excluded value of $$ x=5 v $$ and a denominator of $$ x-5 $$

Question

Clarke Vaughn · Accepted Answer

The simplified form of the expression is $$ \frac{(x + 2)(x - 2)}{(x - 1)} $$, with excluded values $$x = 5$$ and $$x = 1$$.

Consider this product. \( \frac{x^{2}-3 x-10}{x^{2}-6 x+5} \cdot \frac{x-2}{x-5} \) The simplest form of this product has a numerator of \( x+2 \) The expression has an excluded value of \( x=5 v \) and a denominator of \( x-5 \)

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Consider this product. \( \frac{x^{2}-3 x-10}{x^{2}-6 x+5} \cdot \frac{x-2}{x-5} \) The simplest form of this product has a numerator of \( x+2 \) The expression has an excluded value of \( x=5 v \) and a denominator of \( x-5 \)

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Respuesta rápida

Solución paso a paso

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