$$ 1 \leftarrow \quad \begin{array}{l} ext { (a) } I=P r t ext { for } r \ ext { (b) } S=P(1+r t) ext { for } t\end{array} $$

Question

$$ 1 \leftarrow \quad \begin{array}{l}	ext { (a) } I=P r t 	ext { for } r \ 	ext { (b) } S=P(1+r t) 	ext { for } t\end{array} $$

Powell Haynes · Accepted Answer

For part (a), $$ r = \frac{I}{P t} $$. For part (b), $$ t = \frac{\frac{S}{P} - 1}{r} $$.

\( 1 \leftarrow \quad \begin{array}{l}\text { (a) } I=P r t \text { for } r \\ \text { (b) } S=P(1+r t) \text { for } t\end{array} \)