7. $$ (10 x+4)^{\frac{1}{2}}=(9-3 x)^{\frac{1}{2}} $$ $$ \begin{array}{llll} ext { a. } \frac{13}{5} & ext { b. } \frac{5}{13} & ext { c. } \frac{13}{7} & ext { d. }-7\end{array} $$

Question

7. $$ (10 x+4)^{\frac{1}{2}}=(9-3 x)^{\frac{1}{2}} $$ $$ \begin{array}{llll}	ext { a. } \frac{13}{5} & 	ext { b. } \frac{5}{13} & 	ext { c. } \frac{13}{7} & 	ext { d. }-7\end{array} $$

Mccarthy Campos · Accepted Answer

$$ x = \frac{5}{13} $$. Therefore, the correct answer is b. $$ \frac{5}{13} $$.

7. \( (10 x+4)^{\frac{1}{2}}=(9-3 x)^{\frac{1}{2}} \) \( \begin{array}{llll}\text { a. } \frac{13}{5} & \text { b. } \frac{5}{13} & \text { c. } \frac{13}{7} & \text { d. }-7\end{array} \)

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7. \( (10 x+4)^{\frac{1}{2}}=(9-3 x)^{\frac{1}{2}} \) \( \begin{array}{llll}\text { a. } \frac{13}{5} & \text { b. } \frac{5}{13} & \text { c. } \frac{13}{7} & \text { d. }-7\end{array} \)

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