Suppose \( A \) is a nonsingular square matrix satiszging \( A^{2}=A \) choose correct statement 1. \( A \) has no inverse and det(A) \( =-1 \) 2. \( \operatorname{det}(A)=0 \) or \( \operatorname{det}(A)=-1 \) 3. A has no inverse 4. none of the given options 5. \( A=I \), where \( \pm \) is the corresponding identity matrix 6. \( \operatorname{det}(A)=2 \) or \( \operatorname{det}(A)=-1 \)

5) Sea una función lineal cuya gráfica pasa por los puntos \( (6,3) \) y \( (-2,-1) \). a) Determine la función b) ¿Cuál es el valor de \( f(-3) \) y de \( f(8) \) ? c) ¿Es creciente o decreciente?

A. \( 4 x^{2} y\left(x z^{2}+5 w x y+3\right) \).

Solve the following equations and inequalities analytically. Support your solutions graphically. \( \begin{array}{lll}\begin{array}{ll}\text { (a) }|2 x+1|+3=5 & \text { (b) }|2 x+1|+3 \leq 5 \\ \text { (c) }|2 x+1|+3 \geq 5\end{array} \\ \text { A. The solution set is the finite set of real numbers }\{ \\ \text { (a) Find the solution for }|2 x+1|+3=5 \text {. Select the correct choice below, and fill in the } \\ \text { answer box if necessary. } \\ \text { expression. Use a comma to separate answers as needed.) } \\ \text { B. The solution set is the interval } \square \text {. } \\ \text { (Type your answer in interval notation. Use integers or fractions for any } \\ \text { numbers in the expression.) } \\ \text { C. The solution set is } \varnothing \text {. }\end{array} \).

(a) Find the solution for \( |2 x+1|+3=5 \). Select the correct choice below, and fill in the answer box if necessary. A. The solution set is the finite set of real numbers \( \{ \). (Simplify your answer. Use integers or fractions for any numbers in the expression. Use a comma to separate answers as needed.) B. The solution set is the interval (Type your answer in interval notation. Use integers or fractions for any numbers in the expression.)

4) Dado el dominio de cada función, determina el recorrido. \( \begin{array}{ll}\text { a. } f(x)=20 x \text { y } \operatorname{Dom}(f)=\{0,1,2,3\} & \text { b. } g(x)=-5 x \text { y } \operatorname{Dom}(g)=\{0,3,6,9\} \\ \text { c. } h(x)=x-3 \text { y } \operatorname{Dom}(h)=\{-2,-1,0,1\} & \text { d. } j(x)=3 x+4 \text { y } \operatorname{Dom}(j)=\{0,5,10,15\}\end{array} \)