2. $$ (1,2),\left\{\begin{array}{l}x-y=-1 \ x+y=3\end{array} ight. $$ 4. $$ (5,2),\left\{\begin{array}{l}x-y=3 \ x+y=6\end{array} ight. $$

Question

2. $$ (1,2),\left\{\begin{array}{l}x-y=-1 \ x+y=3\end{array}ight. $$ 4. $$ (5,2),\left\{\begin{array}{l}x-y=3 \ x+y=6\end{array}ight. $$

Curry Mullins · Accepted Answer

1. For the first system: $$ (x, y) = (1, 2) $$ 2. For the second system: $$ (x, y) = \left(\frac{9}{2}, \frac{3}{2}\right) $$

2. \( (1,2),\left\{\begin{array}{l}x-y=-1 \\ x+y=3\end{array}\right. \) 4. \( (5,2),\left\{\begin{array}{l}x-y=3 \\ x+y=6\end{array}\right. \)