14. $$ f(x)=\log _{2}\left(\frac{x-2}{x+1}\right) $$

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Campbell Wade · Accepted Answer

The domain of $$ f(x) = \log_{2}\left(\frac{x-2}{x+1}\right) $$ is $$ (-\infty, -1) \cup (2, \infty) $$. The function approaches $$ +\infty $$ as $$ x $$ approaches $$ -1 $$ from the left, $$ 0 $$ as $$ x $$ approaches $$ -\infty $$ and $$ +\infty $$, and $$ -\infty $$ as $$ x $$ approaches $$ 2 $$ from the right. The function has vertical asymptotes at $$ x = -1 $$ and $$ x = 2 $$.

14. \( f(x)=\log _{2}\left(\frac{x-2}{x+1}\right) \)

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14. \( f(x)=\log _{2}\left(\frac{x-2}{x+1}\right) \)

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