Solve, triangle \( A B C \) in which \( a=72.5, \angle B=60^{\circ}, \angle C=83^{\circ} \)

في مثلث قائم الزاوية، طول الوتر هو 10 سم وزاوية حادة تساوي 30 درجة. احسب طول الضلع المقابل لهذه الزاوية.

Solve, triangle \( A B C \) in which \( a=72.5, \angle B=60^{\circ}, \angle C=83^{\circ} \)

Law of Sines Score: \( 11 / 25 \quad \) Penalty: 1 off Question In \( \Delta \mathrm{TUV}, u=3.4 \) inches, \( m \angle \mathrm{U}=144^{\circ} \) and \( m \angle \mathrm{~V}=35^{\circ} \). Find the length of \( v \), to the nearest 10 oth of an inch Answer Attempt 1 out of 2

22. Find the exact value of \( \sin (A+B) \), given \( \sin A=-\frac{4}{5}, A \) is in Quadrant \( I I I, \tan B=\frac{15}{17} \) and \( B \) is in Quadrant \( I \).

La distanza \( A C \) di un punto \( A \) da uni piano e 7 cm . Un segmento \( A B \), obliquo al piano e con il punto \( B \) giacente sul piaro stesso, misura \( 7 \cdot \sqrt{2} \mathrm{~cm} \). Quanto misural'an- golo che il segmento \( A B \) forma con la sua proiezione sul piano? \( \left[45^{\circ}\right] \)