\( \begin{array}{ll}\text { 11. } 8+4^{2} \times 2-6 & = \\ \text { 12. } 3^{2}(4+6)+3 & = \\ \text { 13. }(12-6)+27 \div 3^{2} & = \\ \text { 14. } 82^{0}-1+4 \div 2^{2} & =\end{array} \)

Use the parent function \( f(x)=|x| \) to match the description of the transformed graph to the related function. The graph is shifted 4 units to the left. [Select] The graph is reflected across the x-axis. [ Select] The graph is shifted down 1.5 units. [Select] The graph is vertically stretched, shifted 3 units to the right and up 2 [Select]

Resolver \( \log _{2} 64+\log _{2}\left(\frac{1}{4}\right)-\log _{3} 9-\log _{2} \sqrt{2} \)

7. The distance \( (d) \) in miles that a person can see to the horizon is represented by the equation \( d=\sqrt{\frac{3 h}{2}} \), where \( h \) is the height where the person is. ( 1 mile \( =1609.3 \mathrm{~m} \) ). How far can you see to the horizon through an airplane window at a height of 8000 meters? (Note: Conver first the given height of 8000 meters to miles.) \( \begin{array}{llll}\text { a. } 2.73 \text { miles } & \text { b. } 2.74 \text { miles } & \text { c. } 7.46 \text { miles } & \text { d. } 7.64 \text { miles }\end{array} \)

(51) \( \frac{8^{2}+2}{7^{2}-5^{2}}= \)

\( \begin{array}{ll}\text { 11. } 8+4^{2} \times 2-6 & = \\ \text { 12. } 3^{2}(4+6)+3 & = \\ \text { 13. }(12-6)+27 \div 3^{2} & = \\ \text { 14. } 82^{0}-1+4 \div 2^{2} & =\end{array} \)