b Hence show that \( \int_{2}^{3} \ln y \mathrm{~d} y=\ln \left(\frac{27}{4 \mathrm{e}}\right) \)

nction définie par \( f(x)=\frac{L}{x^{2}+1} \)

Show that \( \Gamma\left(\frac{1}{2}\right)=\sqrt{\pi} \)

If the slope of the tangent to the curve: \( y=f(x) \) at any point on it equals \( 6 x+a \), where \( a \) is constant if the equation of the tangent to the curve at the point \( (1,-1) \) is \( y=4- \) \( 5 x \), then the equation of the curve is ... \( \begin{array}{llll}\text { a) } y=3 x^{2}-4 & \text { b) } y=3 x^{2}-11 x+7 & \text { c) } y=3 x^{2}-4 x & \text { d) } y=3 x^{2}-x-3\end{array} \)

3. \( \lim _{x \rightarrow \infty} \frac{x-1}{2 x+5} \)

Determine the indefinite integral \( \int (6x^3 + 4x^2) \, dx \)