If in Binomial distribution $$ n=6, p=0.2, q=0.8 $$ then we can approximate it to normally disputation

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1. For a binomial distribution with parameters $$ n $$ and $$ p $$, a common rule of thumb for the normal approximation is that both $$ np $$ and $$ n(1-p) $$ should be at least 5.

2. Here, we have:
   $$
   n = 6, \quad p = 0.2, \quad q = 1 - p = 0.8
   $$

3. Calculate $$ np $$ and $$ nq $$:
   $$
   np = 6 \times 0.2 = 1.2
   $$
   $$
   nq = 6 \times 0.8 = 4.8
   $$

4. Since $$ np = 1.2 $$ and $$ nq = 4.8 $$ are both less than 5, the conditions for using the normal approximation are not satisfied.

5. Therefore, we cannot reliably approximate this binomial distribution by a normal distribution.
Cannot approximate the binomial distribution with a normal distribution because $$ np = 1.2 $$ and $$ nq = 4.8 $$ are both less than 5.

If in Binomial distribution \( n=6, p=0.2, q=0.8 \) then we can approximate it to normally disputation

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