Identify the $$ L C D $$ in the equation below. $$ \frac{x+4}{x+3}+\frac{12}{x}=\frac{18}{x+3} $$ $$ (x+3)^{2} $$ $$ x $$ $$ x+3 $$ $$ x(x+3) $$

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To find the least common denominator (LCD) in the equation

$$
\frac{x+4}{x+3}+\frac{12}{x}=\frac{18}{x+3},
$$

we need to identify the denominators present in the equation:

1. The first term has a denominator of $$ x + 3 $$.
2. The second term has a denominator of $$ x $$.
3. The right side also has a denominator of $$ x + 3 $$.

Now, we will find the least common denominator by considering all the unique factors from these denominators:

- The denominators are $$ x + 3 $$ and $$ x $$.
- The least common denominator must include each unique factor at its highest power.

Thus, the LCD is:

$$
x(x + 3).
$$

Now, let's confirm that this includes all the denominators:

- $$ x $$ is included.
- $$ x + 3 $$ is included.

Therefore, the least common denominator (LCD) for the equation is

$$
\boxed{x(x + 3)}.
$$
The least common denominator (LCD) is $$ x(x + 3) $$.

Identify the \( L C D \) in the equation below. \( \frac{x+4}{x+3}+\frac{12}{x}=\frac{18}{x+3} \) \( (x+3)^{2} \) \( x \) \( x+3 \) \( x(x+3) \)

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