Question
upstudy study bank question image url

12 Fill in the blanks with \( < \), \( \rangle \), or \( = \) to correctly compare the expressions. \( \sqrt{3}+4 \quad 3+\sqrt{4} \) \( \sqrt{11} \sqrt[3]{90} \)

Ask by French Li. in the United States
Feb 25,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

√3 + 4 > 3 + √4 and √11 < ∛90

Solution

We need to determine which comparison symbol—"<", ">", or "="—should be placed between the following pairs of expressions. 1. Compare: √3 + 4  and  3 + √4 • First expression: √3 + 4   √3 is approximately 1.732, so √3 + 4 ≈ 1.732 + 4 = 5.732. • Second expression: 3 + √4   √4 = 2, so 3 + 2 = 5. Since 5.732 > 5, we conclude that:   √3 + 4 > 3 + √4 2. Compare: √11  and  ∛90   (Here, ∛90 denotes the cube root of 90.) • First expression: √11   √11 ≈ 3.317. • Second expression: ∛90   To approximate, note that ln(90) ≈ 4.5; dividing by 3 gives 1.5, and e^(1.5) ≈ 4.481.   Thus, ∛90 ≈ 4.481. Since 3.317 < 4.481, we have:   √11 < ∛90 So the filled comparisons are:   √3 + 4 > 3 + √4  and  √11 < ∛90

Answered by UpStudy AI and reviewed by a Professional Tutor

error msg
Explain
Simplify this solution

Bonus Knowledge

To compare the expressions \( \sqrt{3} + 4 \) and \( 3 + \sqrt{4} \): First, we simplify \( 3 + \sqrt{4} \) to \( 3 + 2 = 5 \). Now we compute \( \sqrt{3} + 4 \). \( \sqrt{3} \) is approximately 1.732, so \( \sqrt{3} + 4 \approx 1.732 + 4 = 5.732 \). Therefore, \( \sqrt{3} + 4 > 3 + \sqrt{4} \), and we can fill in the first blank with \( > \). Now, let's compare \( \sqrt{11} \) and \( \sqrt[3]{90} \): Calculating \( \sqrt[3]{90} \), we find that \( 90 \) is between \( 64 \) (which is \( 4^3 \)) and \( 125 \) (which is \( 5^3 \)), so \( \sqrt[3]{90} \) is between \( 4 \) and \( 5 \). Meanwhile, \( \sqrt{11} \) is approximately 3.317, which means \( \sqrt{11} < \sqrt[3]{90} \). We can fill in the second blank with \( < \). Putting it all together, we have: \( \sqrt{3}+4 \quad > \quad 3+\sqrt{4} \) \( \sqrt{11} \quad < \quad \sqrt[3]{90} \)

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy