(c) In a certain school, a test counts \( 20 \% \) of the year mark. The year mark counts \( 25 \% \) of final mark. What fraction does the test count of the final mark?

To find the fraction that the test counts of the final mark, we need to consider the relationship between the test mark, the year mark, and the final mark. Let's denote: - \( T \) as the test mark - \( Y \) as the year mark - \( F \) as the final mark Given: - The test counts \( 20\% \) of the year mark: \( T = 0.20Y \) - The year mark counts \( 25\% \) of the final mark: \( Y = 0.25F \) We need to find the fraction that the test counts of the final mark, which is \( \frac{T}{F} \). Substitute the expressions for \( T \) and \( Y \) in terms of \( F \) into the equation for \( \frac{T}{F} \) to find the fraction that the test counts of the final mark. Simplify the expression by following steps: - step0: Solution: \(0.2\times 0.25F\) - step1: Multiply the terms: \(0.05F\) The fraction that the test counts of the final mark is \( 0.05F \), which simplifies to \( \frac{1}{20}F \).