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The product of \( (x-7)^2 \) is \( x^2 - 14x + 49 \).
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To find the product of \( (x-7)^{2} \), we can use the formula for squaring a binomial, which states \( (a-b)^{2} = a^{2} - 2ab + b^{2} \). Here, \( a = x \) and \( b = 7 \). So, applying the formula: \[ (x-7)^{2} = x^{2} - 2(x)(7) + 7^{2} \] This simplifies to: \[ x^{2} - 14x + 49 \] Thus, the product is: \[ x^{2} - 14x + 49 \]