Id the probability using the normal distribution: $$ P(0

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We want to find 
$$
P(0 < z < 0.03) = \Phi(0.03) - \Phi(0),
$$
where $$\Phi(z)$$ is the cumulative distribution function for the standard normal distribution.

1. From the standard normal table, we have
   $$
   \Phi(0) = 0.5000.
   $$
2. For $$z = 0.03$$, the table gives
   $$
   \Phi(0.03) \approx 0.5120.
   $$
3. Therefore,
   $$
   P(0 < z < 0.03) = 0.5120 - 0.5000 = 0.0120.
   $$

The probability, rounded to 4 decimal places, is $$0.0120$$.
The probability $$ P(0 < z < 0.03) $$ is $$0.0120$$.

Id the probability using the normal distribution: . Use 3 The standard Normal Distribution Table and enter the answer to 4 decimal places.

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