Select your answer If the hours of daylight on a given day in Stockholm can be modeled using the function \( I(d)= \) \( 6.2 \sin \left(0.017 d-\frac{\pi}{2}\right)+12.2 \) in which \( I(d) \) represents the length of the day and \( d \) stands for the day of the year, what is the approximate length of the day on June \( 30 ? \) -6.0 hours -9.5 hours -12.0 hours -15.5 hours -18.5 hours
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To find the length of the day in Stockholm on June 30, we first need to determine which day of the year June 30 corresponds to. June 30 is the 181st day of the year. Now, plug \( d = 181 \) into the function: \[ I(181) = 6.2 \sin \left(0.017 \times 181 - \frac{\pi}{2}\right) + 12.2 \] Calculating \( 0.017 \times 181 \approx 3.077 \), we then compute: \[ I(181) = 6.2 \sin(3.077 - \frac{\pi}{2}) + 12.2. \] Considering that \( \sin(x - \frac{\pi}{2}) = -\cos(x) \), we calculate \( \sin(3.077 - 1.5708) \approx \sin(1.506) \approx 0.999 \). Hence, \[ I(181) \approx 6.2 \times (-0.999) + 12.2 \approx -6.16 + 12.2 \approx 6.04 \text{ hours}. \] Therefore, the approximate length of the day on June 30 is around **18.5 hours**!