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Match each expression on the left to its equivalent value on the right. \( \begin{array}{ll}\frac{2}{3} \div \frac{4}{9} & -1 \frac{1}{2} \\ \frac{3}{2} \div(-1) & 1 \frac{3}{4} \\ (-7) \div(-4) & 1 \frac{1}{2}\end{array} \)

Ask by Macdonald Norris. in the United States
Mar 11,2025

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Answer

- \( \frac{2}{3} \div \frac{4}{9} = 1 \frac{1}{2} \) - \( \frac{3}{2} \div (-1) = -1 \frac{1}{2} \) - \( (-7) \div (-4) = 1 \frac{3}{4} \)

Solution

Calculate the value by following steps: - step0: Calculate: \(\frac{3}{2}\div \left(-1\right)\) - step1: Divide the terms: \(-\frac{3}{2}\) Calculate or simplify the expression \( \frac{2}{3} \div \frac{4}{9} \). Calculate the value by following steps: - step0: Calculate: \(\frac{2}{3}\div \frac{4}{9}\) - step1: Multiply by the reciprocal: \(\frac{2}{3}\times \frac{9}{4}\) - step2: Reduce the numbers: \(1\times \frac{3}{2}\) - step3: Multiply: \(\frac{3}{2}\) Calculate or simplify the expression \( (-7) \div(-4) \). Calculate the value by following steps: - step0: Calculate: \(\left(-7\right)\div \left(-4\right)\) - step1: Divide: \(1.75\) Let's evaluate each expression step by step: 1. **For \( \frac{2}{3} \div \frac{4}{9} \)**: - Dividing fractions involves multiplying by the reciprocal. Thus: \[ \frac{2}{3} \div \frac{4}{9} = \frac{2}{3} \times \frac{9}{4} = \frac{2 \times 9}{3 \times 4} = \frac{18}{12} = \frac{3}{2} \] - This is equivalent to \( 1 \frac{1}{2} \) or \( 1.5 \). 2. **For \( \frac{3}{2} \div (-1) \)**: - Dividing by a negative number changes the sign: \[ \frac{3}{2} \div (-1) = -\frac{3}{2} = -1 \frac{1}{2} \text{ or } -1.5 \] 3. **For \( (-7) \div (-4) \)**: - Dividing two negative numbers gives a positive result: \[ (-7) \div (-4) = \frac{7}{4} = 1 \frac{3}{4} \text{ or } 1.75 \] Now, we can match the expressions to their equivalent values: - \( \frac{2}{3} \div \frac{4}{9} \) matches with \( 1 \frac{1}{2} \). - \( \frac{3}{2} \div (-1) \) matches with \( -1 \frac{1}{2} \). - \( (-7) \div (-4) \) matches with \( 1 \frac{3}{4} \). Thus, the matches are: - \( \frac{2}{3} \div \frac{4}{9} \) → \( 1 \frac{1}{2} \) - \( \frac{3}{2} \div (-1) \) → \( -1 \frac{1}{2} \) - \( (-7) \div (-4) \) → \( 1 \frac{3}{4} \)

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To match the expressions on the left to their equivalent values on the right, let's simplify each expression step by step: 1. For \( \frac{2}{3} \div \frac{4}{9} \): - Division of fractions is equivalent to multiplying by the reciprocal. Thus, \[ \frac{2}{3} \div \frac{4}{9} = \frac{2}{3} \times \frac{9}{4} = \frac{2 \times 9}{3 \times 4} = \frac{18}{12} = \frac{3}{2} = 1 \frac{1}{2}. \] 2. For \( \frac{3}{2} \div (-1) \): - Dividing by a negative number makes the fraction negative, so \[ \frac{3}{2} \div (-1) = -\frac{3}{2} = -1 \frac{1}{2}. \] 3. For \( (-7) \div (-4) \): - Dividing two negatives results in a positive, therefore \[ (-7) \div (-4) = \frac{7}{4} = 1 \frac{3}{4}. \] Now, matching the simplified values with the values on the right: - \( \frac{2}{3} \div \frac{4}{9} = 1 \frac{1}{2} \) - \( \frac{3}{2} \div(-1) = -1 \frac{1}{2} \) - \( (-7) \div(-4) = 1 \frac{3}{4} \) So, the final matches are: \(\frac{2}{3} \div \frac{4}{9} \leftrightarrow 1 \frac{1}{2}\) \(\frac{3}{2} \div(-1) \leftrightarrow -1 \frac{1}{2}\) \((-7) \div(-4) \leftrightarrow 1 \frac{3}{4}\)

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