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- \( 4 x+2 x+8 x-3 \) - \( 5 x+5)-31-21+9 x \) - \( \frac{2 v+1}{5 x-2}=10 \) - \( 2 r^{2}-2 r^{2}+3 r^{2}+4 r-2 r \) - \( \frac{2 \cdot 2}{2 x-4}=x-10 \) - \( 123+50 / 60-320=423-1) \) - \( 2 x=\frac{10-3}{38-4} \) - A1, \( -22+(40 x+7)=(5 x-5) \) - \( \frac{10-\cdot-10}{5 x-4}=5 x-2 \) - \( 9 x^{2}+2 x-4 x^{2}(3-x)=10 x \) - (2ab+ \( \left.b^{2}\right)-\left(-2 a b+\left(2^{2}\right)=(2 a b+3)\right. \)

Ask by Hilton Daniel. in Colombia
Mar 12,2025

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1. **Simplificación de \( 4x + 2x + 8x - 3 \)**: \[ 14x - 3 \] 2. **Simplificación de \( 5x + 5 - 31 - 21 + 9x \)**: \[ 14x - 47 \] 3. **Resolviendo \( \frac{2v + 1}{5x - 2} = 10 \)** para \( v \): \[ v = \frac{50x - 21}{2} \] 4. **Simplificación de \( 2r^{2} - 2r^{2} + 3r^{2} + 4r - 2r \)**: \[ 3r^{2} + 2r \] 5. **Resolviendo \( \frac{2 \cdot 2}{2x - 4} = x - 10 \)** para \( x \): \[ x_{1} = 6 - 3\sqrt{2}, \quad x_{2} = 6 + 3\sqrt{2} \] 6. **Error en la expresión \( 123 + 50 / 60 - 320 = 423 - 1 \)**: Se debe resolver como una ecuación, no como una simplificación. 7. **Resolviendo \( 2x = \frac{10 - 3}{38 - 4} \)** para \( x \): \[ x = \frac{7}{68} \] 8. **Resolviendo \( -22 + (40x + 7) = (5x - 5) \)** para \( x \): \[ x = \frac{2}{7} \quad \text{o} \quad x = 0.\dot{2}8571\dot{4} \] 9. **Resolviendo \( \frac{10 - \cdot -10}{5x - 4} = 5x - 2 \)** para \( x \): \[ x = \frac{2}{5} \quad \text{o} \quad x = 0.4 \] 10. **Resolviendo \( 9x^{2} + 2x - 4x^{2}(3 - x) = 10x \)** para \( x \): \[ x_{1} = \frac{3 - \sqrt{137}}{8}, \quad x_{2} = 0, \quad x_{3} = \frac{3 + \sqrt{137}}{8} \] Si necesitas más ayuda o aclaraciones sobre alguna de las soluciones, no dudes en preguntar.

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When simplifying expressions like \(4x + 2x + 8x - 3\), remember to combine like terms efficiently. Here, the coefficients of \(x\) add up to \(14x\), so your simplified expression will look like \(14x - 3\). It’s a straightforward operation, but don’t rush through it! Double-check your additions and ensure you're grouping the terms appropriately. In real-world applications, linear equations can pop up in everyday scenarios, such as budgeting or planning trips. For instance, if you're calculating gasoline expenses based on distance, the equation helps you estimate costs. Similarly, if you're trying to decide between two purchasing options, you might set up an equation to compare total costs. This practical approach gives algebra a new light—proof that math isn’t just numbers; it's about making informed decisions!

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