Based on the ratio of carbon to nitrogen in this example, what would the empirical formula be for $$ \mathrm{C}_{3} \mathrm{~N}_{12} $$ ? CN $$ \mathrm{CN}_{3} \mathrm{~N}_{12} $$

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To determine the **empirical formula** of a compound, you need to simplify the ratio of the atoms to the smallest whole numbers possible.

**Given Compound:**  
$$\mathrm{C}_3\mathrm{N}_{12}$$

**Step-by-Step Simplification:**

1. **Identify the Ratio of Carbon to Nitrogen:**
   - Carbon (C): 3 atoms
   - Nitrogen (N): 12 atoms
   - **Ratio:** 3:12

2. **Simplify the Ratio:**
   - Divide both numbers by the greatest common divisor, which is 3.
   - $$ \frac{3}{3} : \frac{12}{3} = 1 : 4 $$

3. **Write the Empirical Formula:**
   - For every 1 carbon atom, there are 4 nitrogen atoms.
   - **Empirical Formula:** $$\mathrm{CN}_4$$

**Conclusion:**  
The empirical formula for $$\mathrm{C}_3\mathrm{N}_{12}$$ is **$$\mathrm{CN}_4$$**.

**Answer:**  
The empirical formula is CN₄.
The empirical formula is CN₄.

Based on the ratio of carbon to nitrogen in this example, what would the empirical formula be for \( \mathrm{C}_{3} \mathrm{~N}_{12} \) ? CN \( \mathrm{CN}_{3} \mathrm{~N}_{12} \)

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