Question
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Part 1 of 3 Sketch the graph of the quadratic function and the axis of symmety. State the vertex, and give the equation for the axis of symmetry. \( h(x)=(x+5)^{2} \) Use the graphing tool to graph the function as a solid curve and the axis of symmetry wo dashed line. Click to \( \begin{array}{l}\text { onlarge } \\ \text { graph }\end{array} \)

Ask by Washington Smith. in the United States
Mar 11,2025

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The vertex of the function \( h(x) = (x+5)^2 \) is at \((-5, 0)\), and the axis of symmetry is the vertical line \( x = -5 \).

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The Deep Dive

To sketch the graph of the quadratic function \( h(x) = (x + 5)^2 \), start by identifying the vertex. In this case, the vertex is at the point (-5, 0), since the function is in vertex form \( y = (x - h)^2 + k \), where (h, k) is the vertex. The axis of symmetry is the vertical line that runs through the vertex, given by the equation \( x = -5 \). Now you can graph. Start plotting the vertex at (-5, 0). As you move away from the vertex in both directions, the function will rise, forming a U-shape (since it opens upwards). Plot a few additional points, such as (-4, 1) and (-6, 1), to create the curve. For the axis of symmetry, draw a dashed line along \( x = -5 \) to indicate where the graph is mirrored. Voilà! You've got a beautiful parabola!

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