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PRACTICE (1) The Sharks Aquatic Club recently held a fundraiser to raise money for a local charit) The swimmers received money for each lap that they swam during one week. The three swimmers who raised the most money were Rita, John, and Rodell. Together, they swam a total of 2125 laps. John swam three times as many laps as Rita, and Rodell swam 25 more laps than John. How many laps did each swimmer swim?

Ask by Schwartz Fuentes. in the United States
Feb 26,2025

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Tutor-Verified Answer

Answer

Rita swam 300 laps, John swam 900 laps, and Rodell swam 925 laps.

Solution

Let Rita’s laps be R, John’s be J, and Rodell’s be D. The problem gives us the following equations: 1. R + J + D = 2125 2. J = 3R 3. D = J + 25 Substitute J = 3R into the equation for D to get D = 3R + 25. Now substitute J and D in the total laps equation: R + 3R + (3R + 25) = 2125 Combine like terms: 7R + 25 = 2125 Subtract 25 from both sides: 7R = 2100 Divide both sides by 7: R = 300 Now, using J = 3R and D = 3R + 25: J = 3 × 300 = 900 D = 3 × 300 + 25 = 900 + 25 = 925 Thus, the swimmers completed: Rita = 300 laps, John = 900 laps, Rodell = 925 laps.

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Let’s break down the problem step-by-step to find out how many laps each swimmer swam. 1. **Variables**: Let the number of laps Rita swam be \( r \). Thus, John swam \( 3r \) (three times as many laps as Rita), and Rodell swam \( 3r + 25 \) (25 more laps than John). 2. **Total Laps Equation**: We know that together they swam a total of 2125 laps, so we can set up the equation: \[ r + 3r + (3r + 25) = 2125 \] 3. **Combine Like Terms**: Simplifying that gives us: \[ r + 3r + 3r + 25 = 2125 \] \[ 7r + 25 = 2125 \] 4. **Solve for \( r \)**: Subtract 25 from both sides: \[ 7r = 2100 \] Then divide by 7: \[ r = 300 \] 5. **Calculate the Other Swimmers' Laps**: - Rita: \( r = 300 \) - John: \( 3r = 3 \times 300 = 900 \) - Rodell: \( 3r + 25 = 900 + 25 = 925 \) So, Rita swam 300 laps, John swam 900 laps, and Rodell swam 925 laps!

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Algebra Mexico Feb 26, 2025
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