Solve the following system of equations. Express your answer as an ordered pair in the format \( (a, b) \), with no spaces between the numbers or symbols. \( \begin{array}{l}3 x+4 y=17 \\ -4 x-3 y=-18\end{array} \)

To solve the system of equations, we'll use the method of substitution or elimination. Here, I'll use elimination: 1. The given equations are: \[ 3x + 4y = 17 \quad (1) \] \[ -4x - 3y = -18 \quad (2) \] 2. We can multiply the first equation by 4 and the second equation by 3 to align the coefficients of \(x\): \[ 12x + 16y = 68 \quad (3) \quad \text{(Equation 1 multiplied by 4)} \] \[ -12x - 9y = -54 \quad (4) \quad \text{(Equation 2 multiplied by 3)} \] 3. Now, add equations (3) and (4): \[ (12x - 12x) + (16y - 9y) = 68 - 54 \] \[ 7y = 14 \] Dividing both sides by 7, we find: \[ y = 2 \] 4. Substitute \(y = 2\) back into equation (1) to find \(x\): \[ 3x + 4(2) = 17 \] \[ 3x + 8 = 17 \] \[ 3x = 9 \] \[ x = 3 \] So the solution to the system of equations is \( (3, 2) \).