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Write the linear equation in slope-intercept form. \( \begin{array}{lll}\text { 5. } 2 x+y=17 & \text { 6. } 5 x-y=\frac{1}{4} & \text { 7. }-\frac{1}{2} x+y=10\end{array} \)

Ask by Campos Young. in the United States
Feb 25,2025

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Answer

The slope-intercept forms of the equations are: 5. \( y = -2x + 17 \) 6. \( y = 5x - \frac{1}{4} \) 7. \( y = \frac{1}{2}x + 10 \)

Solution

We want to write each equation in the form y = mx + b, where m is the slope and b is the y-intercept. For equation 5:  2x + y = 17 Subtract 2x from both sides:  y = 17 − 2x Rewrite as:  y = −2x + 17 For equation 6:  5x − y = 1/4 Subtract 5x from both sides:  −y = 1/4 − 5x Multiply both sides by −1:  y = 5x − 1/4 For equation 7:  (−1/2)x + y = 10 Add (1/2)x to both sides:  y = (1/2)x + 10 Thus, the slope-intercept forms are:  5. y = −2x + 17  6. y = 5x − 1/4  7. y = (1/2)x + 10

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To convert each of these equations into slope-intercept form, \(y = mx + b\), we'll solve for \(y\). For \(2x + y = 17\): - Subtract \(2x\) from both sides: \(y = -2x + 17\). For \(5x - y = \frac{1}{4}\): - Add \(y\) to both sides: \(y = 5x - \frac{1}{4}\). For \(-\frac{1}{2}x + y = 10\): - Add \(\frac{1}{2}x\) to both sides: \(y = \frac{1}{2}x + 10\). In slope-intercept form, we have: 1. \(y = -2x + 17\) 2. \(y = 5x - \frac{1}{4}\) 3. \(y = \frac{1}{2}x + 10\)

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