Assume that adults have IQ scores that are normally distributed with a mean of \( \mu=100 \) and a standard deviation \( \sigma=15 \). Find the probability that a randomly selected adult has an IQ less than 127 . Click to view page 1 of the table. Click to view page 2 of the table. The probability that a randomly selected adult has an IQ less than 127 is (Type an integer or decimal rounded to four decimal places as needed.)

To find the probability that a randomly selected adult has an IQ less than 127, we'll first calculate the z-score using the formula: \[ z = \frac{(X - \mu)}{\sigma} \] where \(X\) is the IQ score we're interested in (127), \(\mu\) is the mean (100), and \(\sigma\) is the standard deviation (15). Calculating the z-score: \[ z = \frac{(127 - 100)}{15} = \frac{27}{15} \approx 1.8 \] Next, we look up the z-score of 1.8 in the standard normal distribution table or use a calculator. The table gives us the cumulative probability for values less than the z-score. The probability corresponding to \(z = 1.8\) is approximately 0.9641. Thus, the probability that a randomly selected adult has an IQ less than 127 is: \[ \boxed{0.9641} \]