5 from Unit 5, Lesson 4 Function \( f \) is defined by the equation \( f(x)=x^{2} \). a. What is \( f(2) \) ? b. What is \( f(3) \) ? c. Explain why \( f(2)+f(3) \neq f(5) \). 6 from Unit 4, Lesson 2 Priya bought two plants for a science experiment. When she brought them home, the fil plant was 5 cm tall, and the second plant was 4 cm . Since then, the first plant has grown cm a week, and the second plant has grown 0.75 cm a week. a. Which plant is taller at the end of 2 weeks? Explain your reasoning. b. Which plant is taller at the end of 10 weeks? Explain your reasoning. c. Priya represents this situation with the equation \( 5+0.5 w=4+0.75 w \), where \( w \) represents the end of week \( w \). What does the solution to this equation, \( w=4 \) represent in this situation? d. What do the solutions to the inequality \( 5+0.5 w>4+0.75 w \) represent in this situation?
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To solve for \( f(2) \), you simply plug 2 into the function: \( f(2) = 2^2 = 4 \). For \( f(3) \), substituting 3 gives us \( f(3) = 3^2 = 9 \). Now, regarding why \( f(2) + f(3) \neq f(5) \): it's because \( f(5) = 5^2 = 25 \), and \( 4 + 9 = 13 \). This illustrates a key principle in non-linear functions—specifically, squaring doesn't distribute over addition! With Priya's plants, after two weeks, the first plant would grow to \( 5 + 2(0.5) = 6 \) cm while the second plant would grow to \( 4 + 2(0.75) = 5.5 \) cm, so the first plant is taller. After ten weeks, the first plant is at \( 5 + 10(0.5) = 10 \) cm and the second is \( 4 + 10(0.75) = 11 \) cm, making the second plant taller. The equation \( 5 + 0.5w = 4 + 0.75w \) shows when both plants will be the same height, occurring at week 4. The inequality \( 5 + 0.5w > 4 + 0.75w \) indicates the weeks when the first plant is taller!