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5 from Unit 5, Lesson 4 Function \( f \) is defined by the equation \( f(x)=x^{2} \). a. What is \( f(2) \) ? b. What is \( f(3) \) ? c. Explain why \( f(2)+f(3) \neq f(5) \). 6 from Unit 4, Lesson 2 Priya bought two plants for a science experiment. When she brought them home, the fil plant was 5 cm tall, and the second plant was 4 cm . Since then, the first plant has grown cm a week, and the second plant has grown 0.75 cm a week. a. Which plant is taller at the end of 2 weeks? Explain your reasoning. b. Which plant is taller at the end of 10 weeks? Explain your reasoning. c. Priya represents this situation with the equation \( 5+0.5 w=4+0.75 w \), where \( w \) represents the end of week \( w \). What does the solution to this equation, \( w=4 \) represent in this situation? d. What do the solutions to the inequality \( 5+0.5 w>4+0.75 w \) represent in this situation?

Ask by Hanson Schneider. in the United States
Mar 17,2025

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**Problem 5** Given \( f(x) = x^2 \): a. \( f(2) = 4 \) b. \( f(3) = 9 \) c. \( f(2) + f(3) = 13 \) but \( f(5) = 25 \), so \( f(2) + f(3) \neq f(5) \). --- **Problem 6** Plants grow as: - First plant: \( h_1(w) = 5 + 0.5w \) - Second plant: \( h_2(w) = 4 + 0.75w \) a. After 2 weeks: - First plant: 6 cm - Second plant: 5.5 cm - First plant is taller. b. After 10 weeks: - First plant: 10 cm - Second plant: 11.5 cm - Second plant is taller. c. Equation \( 5 + 0.5w = 4 + 0.75w \) shows when both plants are equal. Solving gives \( w = 4 \) weeks. d. Inequality \( 5 + 0.5w > 4 + 0.75w \) shows that the first plant is taller before 4 weeks.

Solution

**Problem 5** Given the function \( f(x)=x^2 \): a. Compute \( f(2) \): \[ f(2)=2^2=4 \] b. Compute \( f(3) \): \[ f(3)=3^2=9 \] c. Explain why \( f(2)+f(3) \neq f(5) \): We have: \[ f(2)+f(3)=4+9=13 \] and \[ f(5)=5^2=25 \] Since \( 13 \neq 25 \), the equation \( f(2)+f(3)=f(5) \) does not hold. This shows that in general, for a function like \( f(x)=x^2 \), it is not true that the sum of the images equals the image of the sum. --- **Problem 6** Let the first plant's height be represented by: \[ h_1(w)=5+0.5w \] and the second plant's height be represented by: \[ h_2(w)=4+0.75w, \] where \( w \) is the number of weeks. a. **Which plant is taller at the end of 2 weeks?** Calculate the heights at \( w=2 \): \[ h_1(2)=5+0.5(2)=5+1=6 \quad \text{cm} \] \[ h_2(2)=4+0.75(2)=4+1.5=5.5 \quad \text{cm} \] Since \( 6 > 5.5 \), the first plant is taller at the end of 2 weeks. b. **Which plant is taller at the end of 10 weeks?** Calculate the heights at \( w=10 \): \[ h_1(10)=5+0.5(10)=5+5=10 \quad \text{cm} \] \[ h_2(10)=4+0.75(10)=4+7.5=11.5 \quad \text{cm} \] Since \( 11.5 > 10 \), the second plant is taller at the end of 10 weeks. c. **Interpret the equation \( 5+0.5w=4+0.75w \) and its solution \( w=4 \):** The equation \( 5+0.5w=4+0.75w \) represents the week when both plants have the same height. Solving for \( w \): \[ 5+0.5w=4+0.75w \] Subtract \( 4 \) from both sides: \[ 1+0.5w=0.75w \] Subtract \( 0.5w \) from both sides: \[ 1=0.25w \] Divide both sides by \( 0.25 \): \[ w=4 \] Thus, \( w=4 \) means that at the end of 4 weeks, both plants are of equal height. d. **Interpret the inequality \( 5+0.5w>4+0.75w \) and its solution:** Solve the inequality: \[ 5+0.5w>4+0.75w \] Subtract \( 4 \) from both sides: \[ 1+0.5w>0.75w \] Subtract \( 0.5w \) from both sides: \[ 1>0.25w \] Divide both sides by \( 0.25 \): \[ w<4 \] This inequality indicates that for \( w<4 \) (i.e., before 4 weeks pass), the height of the first plant is greater than the height of the second plant.

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To solve for \( f(2) \), you simply plug 2 into the function: \( f(2) = 2^2 = 4 \). For \( f(3) \), substituting 3 gives us \( f(3) = 3^2 = 9 \). Now, regarding why \( f(2) + f(3) \neq f(5) \): it's because \( f(5) = 5^2 = 25 \), and \( 4 + 9 = 13 \). This illustrates a key principle in non-linear functions—specifically, squaring doesn't distribute over addition! With Priya's plants, after two weeks, the first plant would grow to \( 5 + 2(0.5) = 6 \) cm while the second plant would grow to \( 4 + 2(0.75) = 5.5 \) cm, so the first plant is taller. After ten weeks, the first plant is at \( 5 + 10(0.5) = 10 \) cm and the second is \( 4 + 10(0.75) = 11 \) cm, making the second plant taller. The equation \( 5 + 0.5w = 4 + 0.75w \) shows when both plants will be the same height, occurring at week 4. The inequality \( 5 + 0.5w > 4 + 0.75w \) indicates the weeks when the first plant is taller!

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