Use the information listed below to solve parts a through h Suppose that the demand and price for a certain model of a youth wristwatch are related by the following equation, where p is the price (in dollars) and q is the quantity demanded (in hundreds). \( \mathrm{p}=\mathrm{D}(\mathrm{q})=24-1.25 \mathrm{q} \) Find the price at each level of demand. Answer parts a through d.

To solve the problem, we will use the demand equation given: \[ p = D(q) = 24 - 1.25q \] where \( p \) is the price in dollars and \( q \) is the quantity demanded in hundreds. ### Part a: Find the price when \( q = 0 \) Substituting \( q = 0 \) into the demand equation: \[ p = 24 - 1.25(0) = 24 \] So, when \( q = 0 \), the price \( p \) is **$24**. ### Part b: Find the price when \( q = 1 \) Substituting \( q = 1 \) into the demand equation: \[ p = 24 - 1.25(1) = 24 - 1.25 = 22.75 \] So, when \( q = 1 \), the price \( p \) is **$22.75**. ### Part c: Find the price when \( q = 2 \) Substituting \( q = 2 \) into the demand equation: \[ p = 24 - 1.25(2) = 24 - 2.5 = 21.5 \] So, when \( q = 2 \), the price \( p \) is **$21.50**. ### Part d: Find the price when \( q = 3 \) Substituting \( q = 3 \) into the demand equation: \[ p = 24 - 1.25(3) = 24 - 3.75 = 20.25 \] So, when \( q = 3 \), the price \( p \) is **$20.25**. ### Summary of Results - When \( q = 0 \), \( p = 24 \) - When \( q = 1 \), \( p = 22.75 \) - When \( q = 2 \), \( p = 21.50 \) - When \( q = 3 \), \( p = 20.25 \) If you have further parts (e through h) to solve, please provide them!