4.2 .3 $$ \frac{16^{2 y+2} 4^{1-y}}{64 y^{y+2}} $$ $$ \qquad $$ $$ \qquad $$ $$ \qquad $$ $$ \qquad $$ $$ \qquad $$ $$ \qquad $$ 4.3 Solve $$ x $$ in the following equations: 4.3.1 $$ 2^{2 x}=8 $$ $$ \qquad $$ $$ \qquad $$

Question

UpStudy AI · Accepted Answer

To solve the equation $$2^{2x} = 8$$, we can start by expressing both sides of the equation in terms of the same base.

Given that $$8 = 2^3$$, we can rewrite the equation as:
$$2^{2x} = 2^3$$

Since the bases are the same, we can equate the exponents:
$$2x = 3$$

Now, we can solve for $$x$$ by dividing both sides of the equation by 2:
$$x = \frac{3}{2}$$

Therefore, the solution to the equation $$2^{2x} = 8$$ is $$x = \frac{3}{2}$$.
$$ x = \frac{3}{2} $$

4.2 .3

4.3 Solve in the following equations:
4.3.1

Upstudy AI Solution

Answer

Solution

The Deep Dive

Related Questions

Latest Algebra Questions

4.2 .3 4.3 Solve in the following equations: 4.3.1