Question
\( \begin{array}{ll}\text { 5. } \frac{n}{-14}=2 & \text { 6. } 49=-7 x \\ \text { 9. } 6=\frac{c}{7} & \text { 10. } 3 a=-45 \\ \text { 13. }-48=-12 c & \text { 14. } \frac{c}{-8}=9\end{array} \)
Ask by Kelly Moreno. in the United States
Mar 15,2025
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Answer
**5. \( n = -28 \)**
**6. \( x = -7 \)**
**9. \( c = 42 \)**
**10. \( a = -15 \)**
**13. \( c = 4 \)**
**14. \( c = -72 \)**
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Let's solve some of these equations step-by-step! For the first equation, \( \frac{n}{-14} = 2 \), you can find \( n \) by multiplying both sides by -14: \[ n = 2 \times -14 = -28 \] Now, for the equation \( 49 = -7x \), you want to isolate \( x \). Divide both sides by -7: \[ x = \frac{49}{-7} = -7 \] Feeling energized yet? Math is just like a puzzle waiting to be solved—keep going! 😊