\( \int_{-9 \pi / 2}^{9 \pi / 2}(\cos x-4) d x=\square \) (Type an exact answer.)

Calculate the integral \( \int_{-9\pi/2}^{9\pi/2}(\cos(x)-4)dx \). Evaluate the integral by following steps: - step0: Evaluate using formulas and rules: \(\int_{\frac{-9\pi }{2}}^{\frac{9\pi }{2}} \left(\cos\left(x\right)-4\right) dx\) - step1: Rewrite the fraction: \(\int_{-\frac{9\pi }{2}}^{\frac{9\pi }{2}} \left(\cos\left(x\right)-4\right) dx\) - step2: Evaluate the integral: \(\int \left(\cos\left(x\right)-4\right) dx\) - step3: Use properties of integrals: \(\int \cos\left(x\right) dx+\int -4 dx\) - step4: Evaluate the integral: \(\sin\left(x\right)+\int -4 dx\) - step5: Evaluate the integral: \(\sin\left(x\right)-4x\) - step6: Return the limits: \(\left(\sin\left(x\right)-4x\right)\bigg |_{-\frac{9\pi }{2}}^{\frac{9\pi }{2}}\) - step7: Calculate the value: \(2-36\pi \) The integral of \( \cos(x) - 4 \) from \( -\frac{9\pi}{2} \) to \( \frac{9\pi}{2} \) is \( 2 - 36\pi \).