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\( 1=10+\sqrt{3-8 x} \) The solution set is

Ask by Paul Robbins. in the United States
Feb 25,2025

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Tutor-Verified Answer

Answer

There is no real solution.

Solution

We start with the equation:   1 = 10 + √(3 – 8x) 1. Isolate the square root by subtracting 10 from both sides:   √(3 – 8x) = 1 – 10   √(3 – 8x) = -9 2. Notice that the square root (√(3 – 8x)) is defined to be nonnegative for real numbers. Since -9 is negative, there is no real x for which this equation holds. 3. Thus, there is no real solution. The solution set is empty.

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The Deep Dive

To solve the equation \( 1 = 10 + \sqrt{3 - 8x} \), first, isolate the square root: \[ \sqrt{3 - 8x} = 1 - 10 \implies \sqrt{3 - 8x} = -9 \] Since the square root function cannot produce a negative result, this indicates that there are no real solutions for \( x \). Therefore, the solution set is empty. Next time you stumble upon an equation with a square root, remember to check if the expression can yield a solution. If the right side ends up negative, as in this case, you can crown the problem a "no-solution" king!

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